Question

# An electric heater which is connected to a 220 V supply line has two resistance coils. A and B of $$24 \Omega$$ resistance each. these coils can be used separately (one at a time), in series or in parallel. calculate the current drawn when:Only one coil A is usedcoils A and B are used in series

Solution

## ➡When Series R = R1 + R2R = 24 + 24R = 48 ohmV = R × I ( Ohm's law )I = V / RI = 220 / 48 = 4.583333333 Amp➡When parallel 1 / R = 1 / 24 + 1 / 241 / R = 2 / 241 / R = 1 / 12R = 12 ohmI = V / RI = 220 / 12I = 18.33333333 AmpPhysics

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