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Question

An electric heater which is connected to a 220 V supply line has two resistance coils. A and B of $$ 24 \Omega $$ resistance each. these coils can be used separately (one at a time), in series or in parallel. calculate the current drawn when:
  1. Only one coil A is used
  2. coils A and B are used in series


Solution

➡When Series 

R = R1 + R2

R = 24 + 24

R = 48 ohm

V = R × I ( Ohm's law )

I = V / R

I = 220 / 48 = 4.583333333 Amp

➡When parallel 

1 / R = 1 / 24 + 1 / 24

1 / R = 2 / 24

1 / R = 1 / 12

R = 12 ohm

I = V / R

I = 220 / 12

I = 18.33333333 Amp


Physics

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