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Question

An electrical appliance having a resistance of 200Ω is operated at 200 V. Calculate the energy consumed by the appliance in  5 minutes (i) in joule, (ii) in kWh.
 


Solution

(i) R=200 ΩV=200 Vt=5 mins=300 s

Now, energy consumed, H=V2Rt=2002200×300=60000 J

(ii) P=V2R=2002200=200 W=0.2kW

t=5 mins=560 h=112 h

Energy consumed, H=Pt=0.2×112=0.0167 kWh


Physics
Concise Physics
Standard X

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