Question

An electrical appliance of 500 W is used for 5 hours per day. Energy consumed in 30 days will be:

• A. 2.5 kWh
• B. 25 kWh
• C. 75 kWh
• D. 35 kWh

Answer 1

The correct option is C 75 kWh

Given: Power = 500 W = $\frac{500}{1000}=0.5kW$
Time of usage per day $=5hours$
Number of days $30days$
Energy consumed = $power\times time\times numberofdays$.

$Energyconsumed=0.5kW\times 5\times 30$
$Energyconsumed=75kWh$.