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Energy

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Question

An electrical appliance of 500 W is used for 5 hours per day. What will be the energy consumed by the appliance in 30 days?

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Solution

Given: Power = 500 W = $\frac{500}{1000} = 0.5 k W$
Time of usage per day $= 5 h o u r s$
Number of days $30 d a y s$
Energy consumed = $p o w e r \times t i m e \times n u m b e r o f d a y s$ .

$E n e r g y c o n s u m e d = 0.5 k W \times 5 \times 30$
$E n e r g y c o n s u m e d = 75 k W h$ .

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