Question

An electromagnetic wave going through vacuum is described by E = $E_{o}sin(kx-\omega t);B=B_{o}sin(kx-\omega t);$. Which of the following equation is true

• A. $E_{o}k=B_o\omega$
• B. $E_o\omega =B_{o}k$
• C. $E_o{B}_o=\omega k$
• D. None of these

Answer 1

The correct option is A

$E_{o}k=B_o\omega$

$\frac{E_0}{B_0}=C.$ also $k=\frac{2\pi }{\lambda }$ and $w=2\pi v$

These relation gives $E_{0}K=B_{0}w$