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Question

An electromagnetic wave of frequency 3 MHz passes from vacuum into a dielectric medium with relative permittivity εr=4 and relative permeability  μr=1, then


Your Answer
A
the wavelength and frequency both remain unchanged.
Your Answer
B
the wavelength is doubled and the frequency remains unchanged
Your Answer
C
the wavelength is doubled and the frequency becomes half.
Correct Answer
D
the wavelength is halved and the frequency remains unchanged.

Solution

The correct option is D the wavelength is halved and the frequency remains unchanged.
Frequency will always be independent of medium.
Here also frequency remains unchanged.

now,
μ(refractive index)=cv                        =1/ε0μ01/εμ                        =εrμr

Since, μr is very close to 1, then
μ(refractive index)=εr 

and given, εr=4
μ(refractive index)=4=2

Variation of wavelength with medium is given by
 λmedium=λvaccumμ(refractive index)             =λ2
Hence, correct answer is option (d).

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