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Question

An electron beam accelerated from rest through a potential difference of 500V in vacuum is allowed to impinge on a surface normally. The incident current is 50μA and if the electrons come to rest on striking the surface the force on it is

A
1.1924×108N
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B
2.1×108N
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C
1.6×108N
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D
1.6×106N
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Solution

The correct option is A 1.1924×108N
Potential difference =500V
incident current =50×106A
Total current is A=50×106A
change of a electron C=1.6×1019C
Total number of electron per second n=Ae=3.125×1014
Total energy KE=eV
=1.6×1019×5000
=8×1016y
force on wall will be equal to change in momentum of n electron is one second.
Let, P= moment and m be the mass of electron
So, KE=P22m
P2=2m×KE
P=3.8×1023
Total force is F=nP
=3.125×1014×3.8×1023
=1.19×108N

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