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Question

# An electron having charge 1.6×10−19 C and mass 9×10−31 kg is moving with 4×106 m/s speed in a magnetic field of 2×10−1 tesla in a circular orbit. The force acting on an electron and the radius of circular orbit will be:

A
12.8×1013N,1.1×104m
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B
1.28×1014N,1.2×103m
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C
1.28×1013N,1.2×104m
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D
1.28×1013N,1.2×103m
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Solution

## The correct option is D 1.28×10−13N,1.2×10−4mThe force acting on electronF=q(v×B)=1.6×10−19(4×106×2×10−1)=1.28×10−13NAlso, F=mv2rr=mv2F=9×10−31×(4×106)21.28×10−13=1.2×10−4 m

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