An electron in H-atom jumps from second excited state to first excited state and then from first excited to ground state. Let the ratio of wavelength, momentum and energy of photons emitted in these two cases be a, b and c respectively. Then

c = \frac{1}{a}

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a = \frac{9}{4}

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b = \frac{5}{27}

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c = \frac{5}{27}

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Solution

The correct options are
A $c = \frac{1}{a}$
C $b = \frac{5}{27}$
D $c = \frac{5}{27}$
As $\frac{1}{λ} = R (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}) a n d P = \frac{h}{λ}$

Also, $E = \frac{h c}{λ}$

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An electron in H-atom jumps from second excited state to first excited state and then from first excited to ground state. Let the ratio of wavelength, momentum and energy of photons emitted in these two cases be a, b and c respectively. Then

The correct options are A c=1a C b=527 D c=527As 1λ=R(1n21−1n22) and P=hλ Also, E=hcλ

The correct options are
A $c = \frac{1}{a}$
C $b = \frac{5}{27}$
D $c = \frac{5}{27}$
As $\frac{1}{λ} = R (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}) a n d P = \frac{h}{λ}$

Also, $E = \frac{h c}{λ}$