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Question

An electron in hydrogen atom first jumps from second excited state to first excited state and then from first excited state to ground state. Let the ratio of wavelength, momentum and energy of photons emitted in these two cases be a, b and c respectively. Then 



A

c=1a

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B

a=94

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C

b=527

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D

c=527

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Solution

The correct options are
A

c=1a


C

b=527


D

c=527


E1λ
 and pE(E=hcλ,p=Ec)

Further E1n2  

b=c and a=1b

and  c=1221321122=527

b=c=527

and  a=275


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