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Question

An electron is fixed at the origin as shown. What is the electric field at A?


A
3.6×1019 N/C ^i
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B
3.6×1010 N/C ^i
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C
3.6×1010 N/C ^i
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D
None of these
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Solution

The correct option is B 3.6×1010 N/C ^i

To calculate the Electric field, we need to know the charge. We know electrons are negatively chargedparticles and one electron has a charge of –1.6 × 10–19 C. Since it is negatively charged its electric field will point towards itself (that is along l )

The second thing we need to know is the distance of charge from the point (where we want to find the Field).

|E|=14πε0|Q|r2|E|=14πε0×1.6×1019(22)3.6×1010N/C(^J)So, E=3.6×1010N/C ^J


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