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Question

An element (atomic mass $$= 100\ g / mol$$) having bcc structure has unit cell edge $$400\ pm$$. Then, density of the element is:


A
10.376 g/cm3
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B
5.188 g/cm3
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C
7.289 g/cm3
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D
2.144 g/cm3
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Solution

The correct option is D $$5.188\ g/cm^{3}$$
$$\rho = \dfrac {Z\times M}{N_{A} \times a^{3}} = \dfrac {2\times 100}{6.023\times 10^{23} \times (400 \times 10^{-10})^{3}}$$

$$= 5.188\ g/cm^{3}$$

Chemistry

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