Question

# An elevator descends into a mine shaft at the rate of 6 m/min. If the descent starts from 10 m above the ground level, how long will it take to reach −350m? [4 MARKS]

Solution

## Calculations: 1 Mark Steps: 2 Marks Result: 1 Mark Given that An elevator descends into a mine shaft at the rate of 6 m/min. The descent starts from 10m above the ground level. Now, the distance descended is denoted by a negative integer. Initial height = +10 m Final depth = −350 m Total distance to be descended by the elevator = (−350) − (+10) = −360 m Time taken by the elevator to descend −6 m = 1 min Thus, time taken by the elevator to descend −360 m = (−360) ÷ (−6) = 60 minutes = 1 hour Hence it will take 1 hour to reach -350m. Mathematics

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