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Question

An elevator descends into a mine shaft at the rate of $$6$$ m/min. If the descent starts from $$10$$ m above ground level, how long will it take to reach $$-350$$ m


A
40 minutes
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B
50 minutes
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C
60 minutes
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D
70 minutes
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Solution

The correct option is C $$60$$ minutes
Distance descended is denoted by a negative integer,

Initial height $$=+10 \ m$$

Final Depth $$=-350 \ m$$

Total distance to be descended by the elevator $$=(-350)-(+10)=-360 \ m$$

Given, the time is taken by the elevator to descend $$-6 \ m=1 \ minute$$

Thus, time taken by the elevator to descend $$-360\ m=\dfrac{(-360)}{(-6)}$$ ------- [from the formula : $$speed=\dfrac{distance}{time}$$]

$$=60 \ minutes$$

Mathematics

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