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Question

An elevator descends into a mine shaft at the rate of $$6\ m/min$$. If the descend stars from $$10\ m$$ above the ground level, how long will it take to reach the shaft $$350\ m$$ below the ground level?


Solution

Rate of elevator $$=6\ m/min$$
and it was started $$10\ m$$ above the ground level 
Depth below ground level $$=350\ m$$
Total depth $$=350+10=360$$
Time taken $$=\dfrac{360}{6}$$ minutes $$=60$$ minutes $$=1$$ hour

Mathematics

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