Question

# An elevator descends into a mine shaft at the rate of $$6$$ meters per minute. If the decent starts from $$10$$ m above the ground level, how long will it take to reach $$-350$$ m (in hours)

Solution

## Consider the elevator to be at constant speed and the destination to be $$350$$m below ground level, the elevator has to travel $$10$$m till the ground, then $$350$$m moreSo, total distance to travel is $$360$$mIf the elevators speed is $$6$$m/min,Time$$=\dfrac{Distance}{Speed}$$$$=\dfrac{360}{6}$$$$=60$$ minutes$$=1$$ hour.MathematicsNCERTStandard VII

Suggest Corrections

0

Similar questions
View More

Same exercise questions
View More

People also searched for
View More