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Question

An elevator is descending with uniform acceleration. To measure the acceleration, a person in the elevator drops a coin at the moment the elevator starts. The coin is 6 ft above the floor of the elevator at the time it is dropped. The person observes that the coin strikes the floor in 1 second. Calculate from acceleration of the elevator.

A
20ft/s2
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B
30ft/s2
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C
200ft/s2
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D
50ft/s2
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Solution

The correct option is A 20ft/s2
Let the acceleration of life be a
acc. of ball w.r.t gourd - acc of life
ar
aball(lift)=ga
=9.8m/s2a=32ft/sa
displacement = s=6ft
t=ls
u=0
s=ut+12at2
=01+12(32a)×1×1=12(32a)
6=12(32a)
a=20ft/s2

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