An energy of 24.6eV is required to remove one of the electrons from a neutral helium atom. The energy (in eV) required to remove both the electrons from a neutral helium atom is :
A
38.2
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B
49.2
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C
51.8
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D
79.0
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Solution
The correct option is D79.0 Energy required to remove second electron from He+1 ion is: =13.6ev×Z2n2 [ n=1 He is in ground state] =13.6×4eV=54.4eV So, total energy required to fully ionise Helium electron =(54.4+24.6)eV=79eV