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Question

An energy of 24.6 eV is required to remove one of the electron from a neutral helium atom. The energy ( in eV) required to remove both the electrons from a neutral helium atom is. (integer only)

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Solution

Given, ionization energy of the neutral He atom is 24.6 eV,

From Bohr's atomic model, the ionization energy of a hydrogen like atom is,

E=13.6Z2n2 .......(1)

From a neutral He atom, energy required to remove the first electron is =24.6 eV

Now it becomes a single electron atom (He+) and we can apply Bohr's model.

Using (1) we get,

E=13.6(2)2(1)2

E=13.6×4=54.4 eV

Total energy required =24.6+54.4=79 eV



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