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Question

An equilateral triangle ABC is inscribed in a circle with centre O. The measures of ∠BOC is

(a) 30°

(b) 60°

(c) 90°

(d) 120°

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Solution

(d) 120°

We are given that an equilateral
ΔABC is inscribed in a circle with centre O. We need to find BOC

We have the following corresponding figure:

We are given AB = BC = AC

Since the sides AB, BC, and AC are these equal chords of the circle.

So, the angle subtended by these chords at the centre will be equal.

Hence

Hence, the correct answer is option (d).


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