Question
An equilateral triangle ABC is inscribed in a circle with centre O. Then, ∠BOC is equal to:
An equilateral triangle ABC is inscribed in a circle with centre O. Then, ∠BOC is equal to:
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Solution
The correct option is D 120°
Given, ΔABC is an equilateral triangle.
If, ∠BAC=60∘
So, ∠BOC=2 ∠BAC=120∘
[The angle subtended by a chord at the centre of a circle is twice the angle subtended by the same chord at any other point on the remaining part of the circle.]
120°
Given, ΔABC is an equilateral triangle.
If, ∠BAC=60∘
So, ∠BOC=2 ∠BAC=120∘
[The angle subtended by a chord at the centre of a circle is twice the angle subtended by the same chord at any other point on the remaining part of the circle.]
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