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Question

An equilateral triangle ABC is inscribed in a circle with centre O. Then, BOC is equal to:


A

30°

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B

60°

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C

90°

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D

120°

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Solution

The correct option is D

120°


Given, ΔABC is an equilateral triangle.
If, BAC=60
So, BOC=2 BAC=120

[The angle subtended by a chord at the centre of a circle is twice the angle subtended by the same chord at any other point on the remaining part of the circle.]


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