CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An equilateral triangle is inscribed in the circle x2+y2=a2 with the vertex at (a,0). The equation of the side opposite to this vertex is

A
2xa=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x+a=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2x+a=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
3x2a=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2x+a=0
A(a,0) be the vertex of the equilateral triangles ABC inscribed in the circle x2+y2=a2
Let M be the middle point of the side BC
then MOA is perpendicular to BC and 0
being the centroid of the triangle OA=2(OM)
So if (h,k) be the coordinates of M
then 2h+a3=0 and 2k+03=0
h=(a/2) and k=0 and
Hence the equation of BC is x=a/22x+a=0

366565_196530_ans_d42406084c734a4da0097cc6931cd62b.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Parametric Representation-Hyperbola
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon