Question

# An express train going towards Delhi is travelling at a speed of 90 km/h. Brakes are applied so as to produce a uniform acceleration of –0.5 m/s2. Find how far the train will go before it is brought to rest.

A

600 m

B

725 m

C

625 m

D

500 m

Solution

## The correct option is C 625 m Here, Initial velocity u=90 km/h =90×10003600 m/s =25 m/s Acceleration a= –0.5 m/s2 Final velicity v=0 v2=u2+2as [s is the distance travelled] 0=252+(2×−0.5×s) s=625 m Hence the distance covered is 625 m.

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