An express train going towards Delhi is travelling at a speed of 90 km/h. Brakes are applied so as to produce a uniform acceleration of –0.5 m/s2. Find how far the train will go before it is brought to rest.
Initial velocity u=90 km/h
Acceleration a= –0.5 m/s2
Final velicity v=0
v2=u2+2as [s is the distance travelled]
Hence the distance covered is 625 m.