Question

# An ice box used for keeping eatables cool has a total wall area of 1 m2 and a wall thickness of 5.0 cm. The thermal conductivity of the ice box is K=0.01 J/moC. It is filled with ice along with eatables on a day when the temperature is 30oC. The latent heat of fusion of ice is 334×102 J/kg. The amount of ice melted in one day is (1 day=86,400 seconds):

A
776 g
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B
7760 g
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C
11520 g
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D
1552 g
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Solution

## The correct option is D 1552 gHeat lost in t second will be, Q1=KAΔθdt=0.01×1×30−05×10−2×86400 Joule=518400 JouleSuppose m Kilogram ice got melted then Q2=mL=m×334000=Q1=518400 so m=518400334000=1.552kg=1552gm

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