Question

An Ideal Gas at 1 bar is heated from $O^{o}C$ to 373K. If its initial volume is 5.46L, the final volume would be

• A. 7.46L
• B. 1.865L
• C. 5.46L
• D. 6L

Answer 1

The correct option is A

7.46L

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$\Rightarrow V_2=\frac{V_1\times T_2}{T_1}=\frac{5.46\times 373}{273}$

$\Rightarrow V_2=7.46L$