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Question

An ideal gas expands in volume from $${10}^{-3} m^3$$ to $${10}^{-2}{m}^{3}$$ at $$300 K$$ against a constant pressure at $${10}^{5} N/m^2$$. The work done is:


A
900J
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B
900kJ
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C
270kJ
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D
600kJ
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Solution

The correct option is C $$- 900 J$$
As we know that, work done due to change in volume against constant pressure is given as-

$$W = - {P}_{ext.} \Delta{V}$$

Given:-

$${V}_{i} = {10}^{-3} \; {m}^{3}$$

$${V}_{f} = {10}^{-2} \; {m}^{3}$$

$${P}_{ext.} = {10}^{5} \; {N}/{{m}^{2}}$$

$$\therefore W = - {10}^{5} \left( {10}^{-2} - {10}^{-3} \right) = - 900 \; J$$

Hence, the correct option is $$\text{A}$$

Chemistry

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