Question

# An ideal gas expands in volume from $${10}^{-3} m^3$$ to $${10}^{-2}{m}^{3}$$ at $$300 K$$ against a constant pressure at $${10}^{5} N/m^2$$. The work done is:

A
900J
B
900kJ
C
270kJ
D
600kJ

Solution

## The correct option is C $$- 900 J$$As we know that, work done due to change in volume against constant pressure is given as-$$W = - {P}_{ext.} \Delta{V}$$Given:-$${V}_{i} = {10}^{-3} \; {m}^{3}$$$${V}_{f} = {10}^{-2} \; {m}^{3}$$$${P}_{ext.} = {10}^{5} \; {N}/{{m}^{2}}$$$$\therefore W = - {10}^{5} \left( {10}^{-2} - {10}^{-3} \right) = - 900 \; J$$Hence, the correct option is $$\text{A}$$Chemistry

Suggest Corrections

0

Similar questions
View More

People also searched for
View More