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An ideal gas in a thermally insulated vessel at internal pressure $$=$$ P$$_1$$, volume $$=$$ V$$_1$$ and absolute temperature $$=$$ T$$_1$$ expands irreversibly against zero external pressure, as shown in the diagram. The final internal pressure, volume and absolute temperature of the gas are P$$_2$$, V$$_2$$ and T$$_2$$, respectively. For this expansion,
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A
q=0
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B
T2=T1
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C
P2V2=P1V1
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D
P2Vγ2=P1Vγ1
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Solution

The correct options are
A $$T_2 = T_1$$
B $$q=0$$
C $$P_2V_2 = P_1 V_1$$
Since container is thermally insulated. So, q $$=$$ 0, and it is a case of free expansion, therefore, W $$=$$ 0 and $$\Delta$$E $$=$$ 0
So, $$T_1 = T_2$$.
Also, $$P_1 V_1 = P_2 V_2$$.

Chemistry

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