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Question

An ideal gas is taken through a cycle $$A \rightarrow B \rightarrow C \rightarrow A$$ as shown in the figure. If the net heat supplied in the cycle is $$5\ J$$, then work done by the gas in the process $$C \rightarrow A$$ is
139590_822f16e2e22e4d83bd86403ebdfce787.png


A
5 J
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B
10 J
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C
15 J
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D
20 J
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Solution

The correct option is A $$-5\ J$$
The correct answer is option(A).
In the cyclic process : $$\Delta=0$$
$$\Delta Q=\Delta W$$
$$\Delta W=W_{A\rightarrow B}+W_{B\rightarrow C}+W_{C\rightarrow A}$$
$$W_{B\rightarrow C}=0$$ (volume remains constant)
$$W_{A\rightarrow B}=P(V_2-V_1)=10(2-1)=10J$$ (pressure remains constant)
Therefore, $$5=10+W_{C\rightarrow A}$$
$$\implies W_{C\rightarrow A}=-5J$$

Physics

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