Question

# An ideal gas is taken through a cycle $$A \rightarrow B \rightarrow C \rightarrow A$$ as shown in the figure. If the net heat supplied in the cycle is $$5\ J$$, then work done by the gas in the process $$C \rightarrow A$$ is

A
5 J
B
10 J
C
15 J
D
20 J

Solution

## The correct option is A $$-5\ J$$The correct answer is option(A).In the cyclic process : $$\Delta=0$$$$\Delta Q=\Delta W$$$$\Delta W=W_{A\rightarrow B}+W_{B\rightarrow C}+W_{C\rightarrow A}$$$$W_{B\rightarrow C}=0$$ (volume remains constant)$$W_{A\rightarrow B}=P(V_2-V_1)=10(2-1)=10J$$ (pressure remains constant)Therefore, $$5=10+W_{C\rightarrow A}$$$$\implies W_{C\rightarrow A}=-5J$$Physics

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