An ideal gas is taken through the cycle A⟶B⟶C⟶A, as shown in the figure. If the net heat supplied to the gas in the is 55J the work done by the gas in the process C⟶A is
A
-5 J
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B
-10 J
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C
-15 J
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D
-20 J
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Solution
The correct option is B -5 J Work done in cyclic process is area under the curve =10J 5=WCA+10 WCA=−5J