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Question


An ideal massless spring S can be compressed 1m by a force of 100N in equilibrium. The same spring is placed at the bottom of a frictionless inclined plane inclined at 30 to the horizontal. A 10kg block M is released from rest at the top of the incline and is brought to rest momentarily after compressing the spring by 2m. If g=10 ms2, what is the speed of mass just before it touches the spring?
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A
20ms1
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B
30ms1
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C
10ms1
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D
40ms1
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Solution

The correct option is A 20ms1
F=kx
k=Fx=1001=100N/m
Ei=Ef

12mv2=12kx2mglsin(θ)
12×10×v2=12×100×(2)2(10)(10)(2sin30)
Solving we get

v=20m/s

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