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Question

An ideal monoatomic gas is taken around the cycle ABCD as shown in figure below. Work done during the cycle is


A
PV
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B
3PV
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C
PV
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D
0
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Solution

The correct option is C PV

Figure shows a cyclic process ABCD in counter clockwise direction.
Work done during AD and BC,WAD=WBC=0
Work done during process AB,(WAB)=P(2VV)=PV
Work done during process CD,(WCD)=2P(V2V)=2PV

Net work done (W)=WAB+WBC+WCD+WDA
=PV2PV=PV

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