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Question

An impulse $$I$$ given to a body changes its velocity from $$ v_{1}$$ to $$v_{2}$$. The increase in the kinetic energy of the body is given by:


A
I(v1+v2)
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B
I(v1+v2)/2
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C
I(v1v2)
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D
I(v1v2)/2
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Solution

The correct option is A $$I(v_{1}+v_{2})/2$$
Impulse, $$I=m(v_2-v_1)$$
Change in $$KE=\dfrac {1}{2}m({v_2}^2-{v_1}^2)=\dfrac {1}{2}m(v_2-v_1)(v_2+v_1)=\dfrac {I(v_2+v_1)}{2}$$

Physics

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