Question

An infinite sheet of charge has a surface charge density of ${10}^{-7}C/m^2$. The separation between two equipotential surfaces whose potentials differ by 5 V is :

• A. 0.64 mm
• B. 0.88 mm
• C. 0.32 mm
• D. $5\times {10}^{-7}m$

Answer 1

The correct option is B 0.88 mm

The electric filed due to charge sheet is $E=\frac{\sigma }{2{ϵ}_0}$

Potential difference $V=Ed$ where $d=$ separation between two surfaces.

or $d=\frac{V}{E}=\frac{2{ϵ}_{0}V}{\sigma }=\frac{2\times 8.85\times {10}^{-12}\times 5}{{10}^{-7}}=0.88\times {10}^{-3}m=0.88mm$