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Question

An infinitely long thin wire carrying a uniform linear static charge density λ is placed along the z-axis. The wire is set into motion along its length with a uniform velocity v= v^kz. Find the poynting vector.

A
λ2v4π2ε0a2^k
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B
λ2v4π2ε0a2^i
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C
λ2v4π2ε0a2^k
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D
λ2v4π2ε0a2^i
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Solution

The correct option is D λ2v4π2ε0a2^k
Electric field due to the infinite long wire, E=λ2πϵ0a^j

Magnetic field due to the motion of the wire, B=μ0i2πa^i=μ0λv2πa^i

Poynting vector, S=1μ0(E×B)

=1μ0(λ2πϵ0a^j×μ0λv2πa^i)

=λ2v4π2ϵ0a2^k

Hence option (A) is correct.


1523395_951933_ans_a4f37c2f48684b61a3019b9babbdb35c.PNG

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