An object 1 cm tall is placed in front of a mirror at a distance of 4 cm- In order to produce an upright image of 3 cm height one needs aA- Convex mirror of radius of curvature 12 cmB- Concave mirror of radius of curvature 12 cmC- Concave mirror of radius of curvature 4 cmD- Plane mirror of height 12 cm

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An object 1 cm tall is placed in front of a mirror at a distance of 4 cm. In order to produce an upright image of 3cm height one needs a

Convex mirror of radius of curvature 12 cm

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Concave mirror of radius of curvature 12 cm

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Concave mirror of radius of curvature 4 cm

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Plane mirror of height 12 cm

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Solution

The correct option is B Concave mirror of radius of curvature 12 cm
Erect and enlarged image can be produced by concave mirror $\frac{I}{O} = \frac{f}{f - u} \Rightarrow \frac{+ 3}{+ 1} = \frac{f}{f - (- 4)}$
$\Rightarrow f = - 6 c m \Rightarrow R = 12 c m$

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An object 1 cm tall is placed in front of a mirror at a distance of 4 cm. In order to produce an upright image of 3cm height one needs a

The correct option is B Concave mirror of radius of curvature 12 cmErect and enlarged image can be produced by concave mirror IO=ff−u⇒+3+1=ff−(−4) ⇒f=−6 cm ⇒ R=12 cm

The correct option is B Concave mirror of radius of curvature 12 cm
Erect and enlarged image can be produced by concave mirror $\frac{I}{O} = \frac{f}{f - u} \Rightarrow \frac{+ 3}{+ 1} = \frac{f}{f - (- 4)}$
$\Rightarrow f = - 6 c m \Rightarrow R = 12 c m$