Question

An object experiences a constant acceleration for $20$s after starting from rest. If it travels a distance $s_1$ in the first $10$s and distance $s_2$ in the remaining $10$s, then the ratio of $\frac{s_2}{s_1}$ is?

Answer 1

Distance in $20$ seconds

$s=0\ast 20+a\times {20}^2/2$

$s=200a$ --(1)

distance travels in first 10 seconds

$s_1=0\times 10+a\times {10}^2/2$

$s_1=50a$ --(2)

distance travels in next 10 seconds

$s_2=s-s_1$

$s_2=200a-50a=150a$--(3)

$\frac{s_2}{s_1}=\frac{150a}{50a}=3$