It is given that,
Focal length
f=−20cm
hi=3ho
The image is three times the size of the object. So there are two cases.
Case 1. For real image
m=−vu=−3
v=3u
Using mirror’s formula
1f=1v+1u
1−20=13u+1u
u=−803cm
Case 2. For virtual image
m=−vu=+3
v=−3u
Again using mirror’s formula
1−20=1−3u+1u
u=−403cm
The possible values of u are −803cmand−403cm.