Question

# An object is placed 30 mm in front of a lens. The distance between the image and object is 120 mm. Which among the following can be correct for the given condition?Focal Length of the lens is 22.5 mmThe lens is diverging in natureThe lens is converging in natureThe focal length of the lens is 37.5 mm

Solution

## The correct options are A Focal Length of the lens is 22.5 mm C The lens is converging in nature D The focal length of the lens is 37.5 mmGiven: Object distance, u=−30 mm, (object is placed on the left side of the mirror. Let image distance  be v and focal length be f.  Here two cases arise: Case I - Image and object are on different side of the lens. Case II - Image and object are on the same side of the lens. Focal length will change for both cases as image distance changes. Case I - Image and object are on different side of the lens. As per sign conventions, u=−30 mm, v=120−30=90 mm Putting the values in lens formula 1f =  1v -  1u 1f = 190 - 1−30 1f = 190 + 130 1f = 1+390 f = 904=22.5 mm Case II - Image and object are on the same side of the lens. As per sign conventions, u=−30 mm, v=−(120+30)=−150 mm Putting the values in lens formula 1f =  1v -  1u 1f = 1−150 - 1−30 1f = −1150 + 130 1f = −1+5150 f = 1504=37.5 mm In both cases positive sign of focal length suggests that its a converging (convex) lens

Suggest corrections