An object is placed at a distance of $25 c m$ on the axis of a concave mirror, having focal length $20 c m$ . Find the lateral magnification of an image

- 4

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- 2

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4

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Solution

The correct option is C $- 4$
For spherical mirrors,
$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$
Thus putting values of u and f we get v=-100cm

Now, lateral magnification = $\frac{- v}{u} = - 4$

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