CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An object is placed infront of a concave mirror of focal length f. A virtual image is formed with a magnification, the object has to moved by a distance

A
f
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
f2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3f2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2f3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A f
In the first case. Let x be the distance of object from the mirror. Then
u = -x
v = + 2x
f = -f
Using 1v+1u=1f
or 12x1x=1f
or x=f2
in the second case, let y be the distance of object from the mirror. Then
u = - y, v = -2y
and f = - f
So 12y1y=1f
y=32f
So, object will have to be moved by a distance of y - x or f.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Combination of Lenses and Mirrors
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon