An object is projected with a velocity of 20m/s making an angle of 45 with horizontal. The equation for the trajectory is h=Ax−Bx2, where h is height, x is horizontal distance, A and B are constants. The ratio A:B is- (g=10m/s2)
horizontal and vertical component of velocity are same and equal to 20cos45o=10√
hence horizontal distance is x=10√t
and vertical distance iss=ut+12at2=10√t−12gt2
Alternatively, y=x(A−Bx)=0 when particle reaches the ground.