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Question

An object is projected with velocity 20ms1 making an angle of 450 with horizontal. The equation for its trajectory is h=AxBx2, where h is the height and x the horizontal distance. The ratio of constants A:B is?

A
1:5
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B
5:1
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C
1:40
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D
40:1
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Solution

The correct option is D 40:1
When a particle is projected at an angle θ with the horizontal with velocity u,the trajectory is given by:
y=xtanθgx22u2cos2θ
y=xtan4510x22×400cos245
=x10x2800×1/2
=x10x2400
=x140x2
A=1,B=140
AB=11/40=401

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