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Question

# An object is put one by one in 3 liquids having different densities. The object floats with 19, 211 and 37 parts of their volumes outside the liquid surface in liquids of densities d1, d2 and d3 respectively. Arrange the densities in ascending order of their magnitude.

A
d1<d2<d3
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B
d1>d2>d3
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C
d1=d2=d3
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D
d1<d3<d2
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Solution

## The correct option is A d1<d2<d319=0.11; 211=0.18; 37=0.43 These are the volumes outside of liquid of densities d1, d2 and d3 respectively. This means buoyant force is maximum for d3 since buoyant force is directly proportional to the density. Hence, d1<d2<d3.

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