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Deceleration/Retardation

An object is ...

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An object is subjected to retardation, dv/dt= -5v, which has initial velocity of 4m/s. Time taken by object to come to rest would be?

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Q. An object, moving with a speed

6.25 m s^{- 1}

, is decelerated at a rate given by

\frac{d v}{d t} = - 2.5 \sqrt{v}

v

is intantaneous velocity. The time taken by the object to come to rest would be:

Q. An object, moving with a speed of 6.25 m/s, is decelerated at a rate given by:

\frac{d v}{d t} = - 2.5 \sqrt{v}

where v is the instantaneous speed. The time taken by the object, to come to rest, would be:

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