The mirror is convex so f = -10 cm
(a)1q=1f−1p=−7.50cm
Image distance is negative thus image is virtual, the image is 7.50 cm behind the mirror.
(b) M=−qp=−7.5030=+0.0250
The magnification is positive so the image is uprigth
(c) from above M=h′h→h′=Mh=0.250×2=0.500cm