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Standard XI

Physics

Equations of Motion

An object of ...

Question

An object of mass $10 k g$ moves at a constant speed of $10 m s^{- 1}$ . A constant force that acts for $4 s$ on the object gives it a speed of $2 m s^{- 1}$ in the opposite direction. The magnitude of force acting on the object is (Take the direction of initial velocity as positive)

3 N

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30 N

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300 N

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0.3 N

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Solution

The correct option is B $30 N$
Taking the direction of intial velocity as positive,
$m = 10 k g; u = 10 m / s; v = - 2 m / s$

Using Newton's 2nd law,
$F = m a$
$\Rightarrow F = \frac{m (v - u)}{t} = \frac{10 (- 2 - 10)}{4} = - 30 N$

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An object of mass 10 kg moves at a constant speed of 10 ms−1. A constant force that acts for 4 s on the object gives it a speed of 2 ms−1 in the opposite direction. The magnitude of force acting on the object is (Take the direction of initial velocity as positive)

The correct option is B 30 N Taking the direction of intial velocity as positive, m=10 kg; u=10 m/s; v=−2 m/s Using Newton's 2nd law, F=ma ⇒F=m(v−u)t=10(−2−10)4=−30 N

An object of mass $10 k g$ moves at a constant speed of $10 m s^{- 1}$ . A constant force that acts for $4 s$ on the object gives it a speed of $2 m s^{- 1}$ in the opposite direction. The magnitude of force acting on the object is (Take the direction of initial velocity as positive)

The correct option is B $30 N$
Taking the direction of intial velocity as positive,
$m = 10 k g; u = 10 m / s; v = - 2 m / s$

Using Newton's 2nd law,
$F = m a$
$\Rightarrow F = \frac{m (v - u)}{t} = \frac{10 (- 2 - 10)}{4} = - 30 N$