CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An object of mass 10 kg, moving with a velocity of 5.6 ms1 on a surface, comes to rest after traveling a distance of 16 m. Then
a. coefficient of friction is 0.1
b. work-done against the friction is 156.8 J
c. retardation of the body is 8.4 ms2.
d. the block comes to rest in 1 sec

A
a & b are correct
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
b & c are correct
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
c & d are correct
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a, b & c are correct
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A a & b are correct
We have,
s=16 m,v=0
v2u2=2μgs
u=2μgs
μ=5.622×10×16
μ=0.0980.1
Now,
Work done,
W=μmgs=0.098×10×10×16=156.8 J
Also,
ma=μmga=0.98m/s2
v=u+at0=5.60.98×tt=5.71s

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
What's with All the Tension in the Room?
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon