wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An object of uniform density is allowed to float in water kept in a beaker. The object has triangular cross-section as shown in the figure. If the water pressure measured at the three points A,B and C below the object are PA,PB and PC respectively, then:


A
PA>PB>PC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
PA>PB<PC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
PA=PB=PC
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
PA=PB<PC
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C PA=PB=PC
As we know, P=ρgh
Hence, at the same vertical height of a static fluid, pressure remains constant (unless fluid is accelerated).

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon