Question

An object undergoes an acceleration of $10m/{\sec }^2$ starting from rest. Find the distance traveled in 5 sec?

Answer 1

Given,

$a=10m/s^2$

$u=0m/s$

$t=5sec$

From 2nd equation of motion,

$S=ut+\frac{1}{2}a{t}^2$

$S=0\times 5+\frac{1}{2}\times 10\times 5\times 5$

$S=0+125$

$S=125m$