An old man goes for morning walk on a semi-circular track of radius $28 m$ , if he starts from one end of the track and reaches to other end, the distance covered by the man will be
(Take $π = \frac{22}{7}$ )

80 m

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75 m

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88 m

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68 m

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Solution

The correct option is C $88 m$
Distance covered by the man will be the length of the semi-circular track i.e. $D = π r = \frac{22}{7} \times 28 = 88 m$

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An old man goes for morning walk on a semi-circular track of radius 28 m, if he starts from one end of the track and reaches to other end, the distance covered by the man will be (Take π=227)

The correct option is C 88 mDistance covered by the man will be the length of the semi-circular track i.e. D=πr=227×28=88 m

An old man goes for morning walk on a semi-circular track of radius $28 m$ , if he starts from one end of the track and reaches to other end, the distance covered by the man will be
(Take $π = \frac{22}{7}$ )

The correct option is C $88 m$
Distance covered by the man will be the length of the semi-circular track i.e. $D = π r = \frac{22}{7} \times 28 = 88 m$